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Line 
ℓ has equation 
y=x-3. Find the distance between 
ℓ and the point 
E(-1,3).
Round your answer to the nearest tenth.

Line \ell has equation y=x3 y=x-3 . Find the distance between \ell and the point E(1,3) E(-1,3) .\newlineRound your answer to the nearest tenth.

Full solution

Q. Line \ell has equation y=x3 y=x-3 . Find the distance between \ell and the point E(1,3) E(-1,3) .\newlineRound your answer to the nearest tenth.
  1. Identify Slope and Point: Identify the slope and a point on line \ell. The equation of line \ell is y=x3y = x - 3, which is in slope-intercept form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. The slope of line \ell is 11 (since the coefficient of xx is 11), and the y-intercept is \ell00. A point on line \ell can be found by plugging in any value for xx. For simplicity, we can use the y-intercept point \ell33.
  2. Find Perpendicular Line Equation: Find the equation of the line perpendicular to \ell that passes through point E(1,3)E(-1, 3). The slope of a line perpendicular to \ell will be the negative reciprocal of the slope of \ell. Since the slope of \ell is 11, the slope of the perpendicular line will be 1-1. Using the point-slope form of the equation of a line, yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line, we can plug in the slope and the coordinates of point E(1,3)E(-1, 3)00 to find the equation of the perpendicular line. E(1,3)E(-1, 3)11 E(1,3)E(-1, 3)22 E(1,3)E(-1, 3)33 E(1,3)E(-1, 3)44
  3. Find Point of Intersection: Find the point of intersection between line \ell and the perpendicular line.\newlineTo find the point of intersection, we set the equations of the two lines equal to each other and solve for xx.\newlinex3=x+2x - 3 = -x + 2\newline2x=52x = 5\newlinex=52x = \frac{5}{2}\newlineNow, plug xx back into the equation of line \ell to find the corresponding yy-coordinate.\newliney=(52)3y = \left(\frac{5}{2}\right) - 3\newliney=5262y = \frac{5}{2} - \frac{6}{2}\newlinexx00\newlineThe point of intersection is xx11.
  4. Calculate Distance: Calculate the distance between point E and the point of intersection.\newlineThe distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:\newlineDistance = ((x2x1)2+(y2y1)2)\sqrt{((x_2 - x_1)^2 + (y_2 - y_1)^2)}\newlinePlugging in the coordinates of point E (1,3)(-1, 3) and the point of intersection (52,12)(\frac{5}{2}, -\frac{1}{2}), we get:\newlineDistance = ((52(1))2+(123)2)\sqrt{((\frac{5}{2} - (-1))^2 + (-\frac{1}{2} - 3)^2)}\newlineDistance = ((52+1)2+(123)2)\sqrt{((\frac{5}{2} + 1)^2 + (-\frac{1}{2} - 3)^2)}\newlineDistance = ((52+22)2+(1262)2)\sqrt{((\frac{5}{2} + \frac{2}{2})^2 + (-\frac{1}{2} - \frac{6}{2})^2)}\newlineDistance = ((72)2+(72)2)\sqrt{((\frac{7}{2})^2 + (-\frac{7}{2})^2)}\newlineDistance = (494+494)\sqrt{(\frac{49}{4} + \frac{49}{4})}\newlineDistance = (x2,y2)(x_2, y_2)00\newlineDistance = (x2,y2)(x_2, y_2)11\newlineDistance = (x2,y2)(x_2, y_2)22\newlineDistance \approx 44.9595\newlineRound the answer to the nearest tenth: (x2,y2)(x_2, y_2)33

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