Q. Line ℓ has equation y=x−3. Find the distance between ℓ and the point E(−1,3).Round your answer to the nearest tenth.
Identify Slope and Point: Identify the slope and a point on line ℓ. The equation of line ℓ is y=x−3, which is in slope-intercept formy=mx+b, where m is the slope and b is the y-intercept. The slope of line ℓ is 1 (since the coefficient of x is 1), and the y-intercept is ℓ0. A point on line ℓ can be found by plugging in any value for x. For simplicity, we can use the y-intercept point ℓ3.
Find Perpendicular Line Equation: Find the equation of the line perpendicular to ℓ that passes through point E(−1,3). The slope of a line perpendicular to ℓ will be the negative reciprocal of the slope of ℓ. Since the slope of ℓ is 1, the slope of the perpendicular line will be −1. Using the point-slope form of the equation of a line, y−y1=m(x−x1), where m is the slope and (x1,y1) is a point on the line, we can plug in the slope and the coordinates of point E(−1,3)0 to find the equation of the perpendicular line. E(−1,3)1E(−1,3)2E(−1,3)3E(−1,3)4
Find Point of Intersection: Find the point of intersection between line ℓ and the perpendicular line.To find the point of intersection, we set the equations of the two lines equal to each other and solve for x.x−3=−x+22x=5x=25Now, plug x back into the equation of line ℓ to find the corresponding y-coordinate.y=(25)−3y=25−26x0The point of intersection is x1.
Calculate Distance: Calculate the distance between point E and the point of intersection.The distance between two points (x1,y1) and (x2,y2) is given by the formula:Distance = ((x2−x1)2+(y2−y1)2)Plugging in the coordinates of point E (−1,3) and the point of intersection (25,−21), we get:Distance = ((25−(−1))2+(−21−3)2)Distance = ((25+1)2+(−21−3)2)Distance = ((25+22)2+(−21−26)2)Distance = ((27)2+(−27)2)Distance = (449+449)Distance = (x2,y2)0Distance = (x2,y2)1Distance = (x2,y2)2Distance \approx 4.95Round the answer to the nearest tenth: (x2,y2)3
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