Linda jarred 10 liters of jam after 2 days. How much jam did Linda jar if she spent 3 days making jam? Assume the relationship is directly proportional. _____ liters

Identify values, set up proportion: Step 1: Identify the known values and set up the proportion. Linda jarred 10 liters in 2 days. We need to find out how much she jars in 3 days, let's call this x liters. Set up the proportion based on the known values: 10 liters / 2 days = x liters / 3 daysCross-multiply to solve: Step 2: Cross-multiply to solve for x. Cross-multiplying gives: 10 * 3 = 2 * x 30 = 2xSolve for x: Step 3: Solve for x. Divide both sides by 2 to isolate x: 30 / 2 = x 15 = x

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Linda jarred $10\,\text{liters}$ of jam after $2\,\text{days}$ . How much jam did Linda jar if she spent $3\,\text{days}$ making jam? Assume the relationship is directly proportional. $\newline$ $\_\_\_\_\_$ liters

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Grade 8

Solve proportions: word problems

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Q. Linda jarred

10\,\text{liters}

of jam after

2\,\text{days}

. How much jam did Linda jar if she spent

3\,\text{days}

making jam? Assume the relationship is directly proportional.

\newline

\_\_\_\_\_

liters

Identify values, set up proportion: Step $1$ : Identify the known values and set up the proportion. Linda jarred $10$ liters in $2$ days. We need to find out how much she jars in $3$ days, let's call this $x$ liters. Set up the proportion based on the known values: $\frac{10 \text{ liters}}{2 \text{ days}} = \frac{x \text{ liters}}{3 \text{ days}}$
Cross-multiply to solve: Step $2$ : Cross-multiply to solve for $x$ . Cross-multiplying gives: $10 \times 3 = 2 \times x$ $30 = 2x$
Solve for x: Step $3$ : Solve for x. $\newline$ Divide both sides by $2$ to isolate x: $\newline$ $\frac{30}{2} = x$ $\newline$ $15 = x$