Factor Out Highest Power: To find the limit of the given function as x approaches negative infinity, we first need to simplify the expression to a form that will allow us to evaluate the limit directly. We can start by factoring out the highest power of x in the numerator.
Simplify Square Root: Factor out x4 from the square root in the numerator to simplify the expression inside the square root.16x4−8x2=x4⋅16−x28Since x4=x2, we have:16x4−8x2=x2⋅16−x28
Rewrite Limit Expression: Now we can rewrite the original limit expression using the simplified form of the numerator: limx→−∞(16x4−8x2)/(x2−2)=limx→−∞(x2⋅16−8/x2)/(x2−2)
Divide by x2: Next, we divide both the numerator and the denominator by x2, the highest power of x in the denominator, to simplify the expression further.\lim_{x \to -\infty}\left(\frac{x^\(2\) \sqrt{\(16\) - \frac{\(8\)}{x^\(2\)}}}{x^\(2\) - \(2\)}\right) = \lim_{x \to -\infty}\left(\frac{\sqrt{\(16\) - \frac{\(8\)}{x^\(2\)}}}{\(1\) - \frac{\(2\)}{x^\(2\)}}\right)
Simplify Further: As \(x\) approaches negative infinity, the terms \(\frac{8}{x^2}\) and \(\frac{2}{x^2}\) in the expression will approach \(0\). Therefore, we can simplify the expression to:\(\newline\)\[\lim_{x \to -\infty}\left(\frac{\sqrt{16 - \frac{8}{x^2}}}{1 - \frac{2}{x^2}}\right) = \lim_{x \to -\infty}\left(\frac{\sqrt{16}}{1}\right)
Final Limit Calculation: Since the square root of 16 is 4, and the denominator is 1, the limit simplifies to: limx→−∞(16)/(1)=14=4
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