Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Let 
R_(1) and 
R_(2) be relations on the set 
{1,2,dots,50} such that 
R_(1)={(p,p^(n)):} : is a prime and 
n >= 0 is an integer 
} and 
R_(2)={(p,p^(n)):p:} is a prime and 
n=0 or 1
}. Then, the number of elements in 
R_(1)-R_(2) is 
qquad

Let R1R_{1} and R2R_{2} be relations on the set \{11,22,\dots,5050\} such that R1={(p,pn)}:pR_{1}=\{(p,p^{n})\}: p is a prime and n0n \geq 0 is an integer } and R2={(p,pn)}:pR_{2}=\{(p,p^{n})\}:p is a prime and n=0n=0 or 11. Then, the number of elements in R1R2R_{1}-R_{2} is ______.

Full solution

Q. Let R1R_{1} and R2R_{2} be relations on the set \{11,22,\dots,5050\} such that R1={(p,pn)}:pR_{1}=\{(p,p^{n})\}: p is a prime and n0n \geq 0 is an integer } and R2={(p,pn)}:pR_{2}=\{(p,p^{n})\}:p is a prime and n=0n=0 or 11. Then, the number of elements in R1R2R_{1}-R_{2} is ______.
  1. Define R1R_{1} and R2R_{2}: R1R_{1} includes pairs (p,pn)(p, p^n) where pp is prime and nn is any non-negative integer. R2R_{2} includes pairs (p,pn)(p, p^n) where pp is prime and nn is R2R_{2}00 or R2R_{2}11.
  2. Find pairs in R1R2R_{1} - R_{2}: To find R1R2R_{1} - R_{2}, we need to count the pairs in R1R_{1} that are not in R2R_{2}. This means we're looking for pairs where nn is greater than 11.
  3. Identify primes in set: The primes in the set {1,2,,50}\{1,2,\ldots,50\} are 22, 33, 55, 77, 1111, 1313, 1717, 1919, 2323, 2200, 2211, 2222, 2233, 2244, and 2255. That's 2266 primes.
  4. Calculate powers of primes: For each prime pp, there are infinite values of nn where n > 1, but since we're limited to the set {1,2,...,50}\{1,2,...,50\}, we need to count the powers of pp that are less than or equal to 5050.
  5. Example with prime 22: Let's take an example: for p=2p = 2, the powers are 222^2, 232^3, ..., up to the largest power of 22 that is less than or equal to 5050. That's 25=322^5 = 32. So we have 222^2, 232^3, 242^4, and 252^5.
  6. Repeat for each prime: We repeat this process for each prime, but we must be careful not to count any power of a prime that is greater than 5050.
  7. Final count of powers: After calculating, we find that the powers of primes less than or equal to 5050 for each prime are: 222^2, 232^3, 242^4, 252^5, 323^2, 333^3, 343^4, 525^2, 535^3, 222^200, 222^211, 222^222, 222^233, 222^244, 222^255, 222^266, 222^277, 222^288, 222^299, 232^300, 232^311, and 232^322.
  8. Final count of powers: After calculating, we find that the powers of primes less than or equal to 5050 for each prime are: 222^2, 232^3, 242^4, 252^5, 323^2, 333^3, 343^4, 525^2, 535^3, 222^200, 222^211, 222^222, 222^233, 222^244, 222^255, 222^266, 222^277, 222^288, 222^299, 232^300, 232^311, and 232^322. Counting these, we get 232^333 powers of 232^344, 232^355 powers of 232^355, 232^344 powers of 232^388, 232^344 powers of 242^400, and 242^411 power each for the rest of the primes. That's 242^422 elements.

More problems from One-step inequalities: word problems