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Let aa, bb, cc be the three rational numbers where a=23a = \frac{2}{3}, b=45b = \frac{4}{5} and c=56c = -\frac{5}{6} \newlineVerify: a+(b+c)=(a+b)+ca + (b + c) = (a + b) + c

Full solution

Q. Let aa, bb, cc be the three rational numbers where a=23a = \frac{2}{3}, b=45b = \frac{4}{5} and c=56c = -\frac{5}{6} \newlineVerify: a+(b+c)=(a+b)+ca + (b + c) = (a + b) + c
  1. Calculate b+cb + c: Calculate b+cb + c:b+c=45+(56)=(2430)+(2530)=130b + c = \frac{4}{5} + \left(-\frac{5}{6}\right) = \left(\frac{24}{30}\right) + \left(-\frac{25}{30}\right) = -\frac{1}{30}.
  2. Calculate a+(b+c)a + (b + c): Calculate a+(b+c)a + (b + c):a+(b+c)=23+(130)=(2030)+(130)=1930a + (b + c) = \frac{2}{3} + \left(-\frac{1}{30}\right) = \left(\frac{20}{30}\right) + \left(-\frac{1}{30}\right) = \frac{19}{30}.
  3. Calculate a+ba + b: Calculate a+ba + b:a+b=23+45=(1015)+(1215)=2215a + b = \frac{2}{3} + \frac{4}{5} = \left(\frac{10}{15}\right) + \left(\frac{12}{15}\right) = \frac{22}{15}.
  4. Calculate (a+b)+c(a + b) + c: Calculate (a+b)+c(a + b) + c:(a+b)+c=2215+(56)=(4430)+(2530)=1930(a + b) + c = \frac{22}{15} + \left(-\frac{5}{6}\right) = \left(\frac{44}{30}\right) + \left(-\frac{25}{30}\right) = \frac{19}{30}.

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