Line g has an equation of y=2x+1. Line h includes the point (-5,2) and is perpendicular to line g. What is the equation of line h ?

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Determine slope of line g: Determine the slope of line g. The equation of line g is given by y = 2x + 1. The slope of a line in the form y = mx + b is m, where m is the coefficient of x. Therefore, the slope of line g is 2.Find slope of line h: Find the slope of line h. Since line h is perpendicular to line g, its slope will be the negative reciprocal of the slope of line g. The negative reciprocal of 2 is -1/2.Use point-slope form: Use the point-slope form to write the equation of line h. The point-slope form of a line is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We have the slope of line h as -1/2 and the point (-5, 2). Plugging these values into the point-slope form gives us y - 2 = -1/2(x - (-5)).Simplify equation of line h: Simplify the equation of line h. Simplify the equation from the previous step to get y - 2 = -1/2(x + 5). Distribute the slope -1/2 across (x + 5) to get y - 2 = -1/2x - 5/2.Solve for y: Solve for y to put the equation in slope-intercept form. Add 2 to both sides of the equation to isolate y on one side: y = -1/2x - 5/2 + 2. Simplify the constant terms: y = -1/2x - 5/2 + 4/2. This simplifies to y = -1/2x - 1/2.

Line $g$ has an equation of $y=2 x+1$ . Line $h$ includes the point $(-5,2)$ and is perpendicular to line $\mathrm{g}$ . What is the equation of line $\mathrm{h}$ ?

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Line g g g has an equation of y=2x+1 y=2 x+1 y=2x+1. Line h h h includes the point (−5,2) (-5,2) (−5,2) and is perpendicular to line g \mathrm{g} g. What is the equation of line h \mathrm{h} h ?

Line $g$ has an equation of $y=2 x+1$ . Line $h$ includes the point $(-5,2)$ and is perpendicular to line $\mathrm{g}$ . What is the equation of line $\mathrm{h}$ ?