Solve. 3x-9x^(2)=-10 Choose 1 answer: (A) x=(7+-sqrt77)/(2) (B) x=(-2+-sqrt13)/(-3) (C) x=(-5+-sqrt305)/(14) (D) x=(-1+-sqrt41)/(-6)

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Rewrite Equation: Rewrite the equation in standard quadratic form. To solve the quadratic equation, we need to set it to zero by moving all terms to one side. 3x - 9x^2 = -10 Add 9x^2 and subtract 3x from both sides to get: 9x^2 - 3x + 10 = 0Identify Coefficients: Identify the coefficients for the quadratic formula. The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0. In our equation, 9x^2 - 3x + 10 = 0, a = 9, b = -3, and c = 10.Substitute into Formula: Substitute the coefficients into the quadratic formula. x = (-(-3) ± √((-3)^2 - 4 * 9 * 10)) / (2 * 9) x = (3 ± √(9 - 360)) / 18 x = (3 ± √(-351)) / 18Simplify Square Root: Simplify the expression under the square root. Since the expression under the square root is negative (-351), we have no real solutions. The equation has complex solutions because the discriminant (b^2 - 4ac) is less than zero.Write Complex Solutions: Write the complex solutions. The complex solutions can be written as: x = (3 ± √(-351)) / 18 x = (3 ± i√351) / 18 Since none of the answer choices are in the form of a complex number, we have made a mistake. We need to recheck our calculations.

Solve. $\newline$ $3 x-9 x^{2}=-10$ $\newline$ Choose $1$ answer: $\newline$ (A) $x=\frac{7 \pm \sqrt{77}}{2}$ $\newline$ (B) $x=\frac{-2 \pm \sqrt{13}}{-3}$ $\newline$ (C) $x=\frac{-5 \pm \sqrt{305}}{14}$ $\newline$ (D) $x=\frac{-1 \pm \sqrt{41}}{-6}$

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