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Mindy and Troy combined ate 9 pieces of wedding cake. Mindy ate 3 pieces of cake and Troy had 
(1)/(4) of the total cake. How many pieces of cake were there in all?

Mindy and Troy combined ate 99 pieces of wedding cake. Mindy ate 33 pieces of cake and Troy had 14 \frac{1}{4} of the total cake. How many pieces of cake were there in all?

Full solution

Q. Mindy and Troy combined ate 99 pieces of wedding cake. Mindy ate 33 pieces of cake and Troy had 14 \frac{1}{4} of the total cake. How many pieces of cake were there in all?
  1. Set Up Equation: Let's denote the total number of pieces of cake as TT. According to the problem, Mindy ate 33 pieces of cake, and Troy ate 14\frac{1}{4} of the total cake. Together, they ate 99 pieces. We can set up the following equation to represent this situation:\newlineMindy's pieces + Troy's pieces = Total pieces eaten\newline3+(14)T=93 + \left(\frac{1}{4}\right)T = 9
  2. Isolate Term: Now we need to solve for TT. To do this, we'll first isolate the term containing TT on one side of the equation. We can subtract 33 from both sides to get:\newline(14)T=93(\frac{1}{4})T = 9 - 3
  3. Perform Subtraction: Perform the subtraction on the right side of the equation: 14T=6\frac{1}{4}T = 6
  4. Multiply Both Sides: To find TT, we need to multiply both sides of the equation by 44 to cancel out the 14\frac{1}{4} on the left side:\newline4×(14)T=6×44 \times \left(\frac{1}{4}\right)T = 6 \times 4
  5. Find Total: Perform the multiplication on both sides:\newlineT=24T = 24

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