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Kaliska is jumping rope.
The vertical height of the center of her rope off the ground 
R(t) (in 
cm ) as a function of time 
t (in seconds) can be modeled by a sinusoidal expression of the form 
a*cos(b*t)+d.
At 
t=0, when she starts jumping, her rope is 
0cm off the ground, which is the minimum. After 
(pi)/(12) seconds, it reaches a height of 
60cm from the ground, which is half of its maximum height.
Find 
R(t).

t should be in radians.

R(t)=◻

Kaliska is jumping rope.\newlineThe vertical height of the center of her rope off the ground R(t) R(t) (in cm \mathrm{cm} ) as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , when she starts jumping, her rope is 0 cm 0 \mathrm{~cm} off the ground, which is the minimum. After π12 \frac{\pi}{12} seconds, it reaches a height of 60 cm 60 \mathrm{~cm} from the ground, which is half of its maximum height.\newlineFind R(t) R(t) .\newlinet t should be in radians.\newlineR(t)= R(t)=\square

Full solution

Q. Kaliska is jumping rope.\newlineThe vertical height of the center of her rope off the ground R(t) R(t) (in cm \mathrm{cm} ) as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , when she starts jumping, her rope is 0 cm 0 \mathrm{~cm} off the ground, which is the minimum. After π12 \frac{\pi}{12} seconds, it reaches a height of 60 cm 60 \mathrm{~cm} from the ground, which is half of its maximum height.\newlineFind R(t) R(t) .\newlinet t should be in radians.\newlineR(t)= R(t)=\square
  1. Rephrasing the function: Let's first rephrase the "What is the function R(t)R(t) that models the vertical height of the center of Kaliska's jump rope off the ground as a function of time?"
  2. Determining the vertical shift: Since the rope starts at 0cm0\,\text{cm} off the ground at t=0t=0, which is the minimum height, we know that the vertical shift dd in the sinusoidal function acos(bt)+da\cos(bt)+d is 00. This is because the cosine function starts at its maximum value when there is no horizontal or vertical shift, and since we're starting at the minimum, the vertical shift must be 00 to flip the cosine wave.
  3. Finding the amplitude: Given that the rope reaches half of its maximum height after π12\frac{\pi}{12} seconds, and this height is 6060 cm, we can deduce that the maximum height of the rope is twice this value, which is 120120 cm. Therefore, the amplitude aa of the sinusoidal function is 120120 cm.
  4. Calculating the value of bb: Now we need to find the value of bb, which is related to the period of the function. Since the rope reaches half of its maximum height at π12\frac{\pi}{12} seconds, and knowing that the cosine function reaches half of its maximum value at π3\frac{\pi}{3} radians (since cos(π3)=12\cos(\frac{\pi}{3}) = \frac{1}{2}), we can set up the equation bπ12=π3b\cdot\frac{\pi}{12} = \frac{\pi}{3} to solve for bb.
  5. Solving for bb: Solving the equation for bb, we get b(π12)=π3b\cdot\left(\frac{\pi}{12}\right) = \frac{\pi}{3}. Multiplying both sides by 12π\frac{12}{\pi} to isolate bb, we get b=(π3)(12π)=4b = \left(\frac{\pi}{3}\right) \cdot \left(\frac{12}{\pi}\right) = 4.
  6. Writing the function R(t)R(t): Now that we have all the parameters for the sinusoidal function, we can write the function R(t)R(t) as R(t)=120cos(4t)+0R(t) = 120\cos(4t)+0, which simplifies to R(t)=120cos(4t)R(t) = 120\cos(4t).

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