Jude factored 28x^(2) as (14 x)(2x^(2)). Yasmin factored 28x^(2) as (7x)(4x). Which of them factored 28x^(2) correctly? Choose 1 answer: (A) Only Jude (B) Only Yasmin (C) Both Jude and Yasmin (D) Neither Jude nor Yasmin

Jude's factoring: Jude's factoring: Jude factored 28x^(2) as (14x)(2x^(2)). Let's check if this is correct by multiplying the factors together. (14x) * (2x^(2)) = 28x^(3), not 28x^(2). This is not the correct factoring of 28x^(2) because the result should be 28x^(2), not 28x^(3).Yasmin's factoring: Yasmin's factoring: Yasmin factored 28x^(2) as (7x)(4x). Let's check if this is correct by multiplying the factors together. (7x) * (4x) = 28x^(2). This is the correct factoring of 28x^(2) because the result is indeed 28x^(2).

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Jude factored
28x^(2) as
(14 x)(2x^(2)).
Yasmin factored
28x^(2) as
(7x)(4x).
Which of them factored
28x^(2) correctly?
Choose 1 answer:
(A) Only Jude
(B) Only Yasmin
(C) Both Jude and Yasmin
(D) Neither Jude nor Yasmin

Jude factored $28x^{2}$ as $(14x)(2x^{2}).$ $\newline$ Yasmin factored $28x^{2}$ as $(7x)(4x).$ $\newline$ Which of them factored $28x^{2}$ correctly? $\newline$ Choose $1$ answer: $\newline$ (A) Only Jude $\newline$ (B) Only Yasmin $\newline$ (C) Both Jude and Yasmin $\newline$ (D) Neither Jude nor Yasmin

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Math Problems

Grade 7

Compare ratios: word problems

Full solution

Q. Jude factored

28x^{2}

(14x)(2x^{2}).

\newline

Yasmin factored

28x^{2}

(7x)(4x).

\newline

Which of them factored

28x^{2}

correctly?

\newline

Choose

1

answer:

\newline

(A) Only Jude

\newline

(B) Only Yasmin

\newline

\newline

(D) Neither Jude nor Yasmin

Jude's factoring: Jude's factoring: Jude factored $28x^{2}$ as $(14x)(2x^{2})$ . Let's check if this is correct by multiplying the factors together. $(14x) \times (2x^{2}) = 28x^{3}$ , not $28x^{2}$ . This is not the correct factoring of $28x^{2}$ because the result should be $28x^{2}$ , not $28x^{3}$ .
Yasmin's factoring: Yasmin's factoring: Yasmin factored $28x^{2}$ as $(7x)(4x)$ . Let's check if this is correct by multiplying the factors together. $(7x) \times (4x) = 28x^{2}$ . This is the correct factoring of $28x^{2}$ because the result is indeed $28x^{2}$ .