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Joseph invests money in an account paying a simple interest of 
9% per year. If 
m represents the amount of money he invests, which expression represents his balance after a year, assuming he makes no additional withdrawals or deposits?

1.009 m

0.09 m

1.09 m

9m

Joseph invests money in an account paying a simple interest of 9% 9 \% per year. If m m represents the amount of money he invests, which expression represents his balance after a year, assuming he makes no additional withdrawals or deposits?\newline1.009m 1.009 m \newline0.09m 0.09 m \newline1.09m 1.09 m \newline9m 9 m

Full solution

Q. Joseph invests money in an account paying a simple interest of 9% 9 \% per year. If m m represents the amount of money he invests, which expression represents his balance after a year, assuming he makes no additional withdrawals or deposits?\newline1.009m 1.009 m \newline0.09m 0.09 m \newline1.09m 1.09 m \newline9m 9 m
  1. Understand Simple Interest Formula: First, we need to understand the formula for simple interest. The formula is:\newlineInterest (II) = Principal (PP) * Rate (RR) * Time (TT)\newlineSince we are looking for the total balance after a year, we will add the interest to the principal amount. The expression for the total balance (BB) after one year will be:\newlineB=P+IB = P + I
  2. Substitute Given Values: Now, let's substitute the given values into the formula. Joseph invests an amount of money represented by mm, the rate is 9%9\% per year, and the time is 11 year.\newlineUsing the formula for Interest:\newlineI=m×9%×1I = m \times 9\% \times 1\newlineConvert the percentage to a decimal by dividing by 100100:\newlineI=m×0.09×1I = m \times 0.09 \times 1
  3. Calculate Interest: Now, calculate the interest:\newlineI=m×0.09I = m \times 0.09
  4. Find Total Balance: Next, we add the interest to the principal to find the total balance after one year:\newlineB=m+IB = m + I\newlineB=m+(m×0.09)B = m + (m \times 0.09)
  5. Simplify Expression: Combine like terms to simplify the expression:\newlineB=m×(1+0.09)B = m \times (1 + 0.09)\newlineB=m×1.09B = m \times 1.09

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