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5 markers cost 
$6.55.
Which equation would help determine the cost of 4 markers?
Choose 1 answer:
(A) 
(4)/(5)=($6.55)/(x)
(B) 
(4)/($6.55)=(x)/(5)
(C) 
(5)/(4)=(x)/($6.55)
(D) 
4quad$6.55

55 markers cost $6.55\$6.55. Which equation would help determine the cost of 44 markers? Choose 11 answer: \newline(A) 45=$6.55x\frac{4}{5}=\frac{\$6.55}{x} \newline(B) 4$6.55=x5\frac{4}{\$6.55}=\frac{x}{5} \newline(C) 54=x$6.55\frac{5}{4}=\frac{x}{\$6.55} \newline(D) 4$6.554\quad\$6.55

Full solution

Q. 55 markers cost $6.55\$6.55. Which equation would help determine the cost of 44 markers? Choose 11 answer: \newline(A) 45=$6.55x\frac{4}{5}=\frac{\$6.55}{x} \newline(B) 4$6.55=x5\frac{4}{\$6.55}=\frac{x}{5} \newline(C) 54=x$6.55\frac{5}{4}=\frac{x}{\$6.55} \newline(D) 4$6.554\quad\$6.55
  1. Understand the problem: Step 11: Understand the problem. We need to find the cost of 44 markers based on the cost of 55 markers. We set up a proportion where one side represents the number of markers and the other side represents the cost.
  2. Set up the proportion: Step 22: Set up the proportion. Since 55 markers cost $6.55\$6.55, we can say that the cost per marker is constant. Therefore, the ratio of the number of markers to the cost should be the same for 44 markers. The correct setup is number of markerscost=number of markerscost\frac{\text{number of markers}}{\text{cost}} = \frac{\text{number of markers}}{\text{cost}}.
  3. Analyze the options: Step 33: Analyze the options. \newlineOption (A) 45\frac{4}{5} = ($6.55)x\frac{(\$6.55)}{x} correctly sets up the proportion where the number of markers is directly proportional to the cost. \newlineOption (B) 4($6.55)\frac{4}{(\$6.55)} = x5\frac{x}{5} incorrectly sets up the proportion, mixing costs and number of markers on different sides.\newlineOption (C) 54\frac{5}{4} = x($6.55)\frac{x}{(\$6.55)} also incorrectly sets up the proportion, reversing the relationship.\newlineOption (D) 4$6.554\quad\$6.55 is not a proportion but just a multiplication, which doesn't help in finding the cost per marker.

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