Is the function v(x) = -x^6 + 4x^2 - 1 even, odd, or neither? Choices: (A)even (B)odd (C)neither

Calculate v(-x): Calculate v(-x) by substituting -x for x in the function v(x). v(-x) = -(-x)^6 + 4(-x)^2 - 1Simplify v(-x): Simplify the function v(-x). v(-x) = -x^6 + 4x^2 - 1Compare v(x) and v(-x): Compare v(x) and v(-x) to determine if they are equal. Since v(x) = -x^6 + 4x^2 - 1 and v(-x) = -x^6 + 4x^2 - 1, we see that v(x) = v(-x).Conclude function type: Conclude whether the function is even, odd, or neither. Because v(x) = v(-x), the function v(x) is even.

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Is the function $v(x) = -x^6 + 4x^2 - 1$ even, odd, or neither? $\newline$ Choices: $\newline$ (A)even $\newline$ (B)odd $\newline$ (C)neither

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Algebra 2

Even and odd functions

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Q. Is the function

v(x) = -x^6 + 4x^2 - 1

even, odd, or neither?

\newline

Choices:

\newline

(A)even

\newline

(B)odd

\newline

(C)neither

Calculate $v(-x)$ : Calculate $v(-x)$ by substituting $-x$ for $x$ in the function $v(x)$ . $v(-x) = -(-x)^6 + 4(-x)^2 - 1$
Simplify $v(-x)$ : Simplify the function $v(-x)$ . $v(-x) = -x^6 + 4x^2 - 1$
Compare $v(x)$ and $v(-x)$ : Compare $v(x)$ and $v(-x)$ to determine if they are equal. $\newline$ Since $v(x) = -x^6 + 4x^2 - 1$ and $v(-x) = -(-x)^6 + 4(-x)^2 - 1$ , we see that $v(x) = v(-x)$ .
Conclude function type: Conclude whether the function is even, odd, or neither. $\newline$ Because $v(x) = v(-x)$ , the function $v(x)$ is even.