Is the function s(x) = -x^4 + 8x^3 - 9x^2 even, odd, or neither? Choices: (A)even (B)odd (C)neither

Substitute -x in s(x): s(x) = -x^4 + 8x^3 - 9x^2 Find s(-x) by substituting -x for x in s(x). s(-x) = -(-x)^4 + 8(-x)^3 - 9(-x)^2Simplify s(-x): s(-x) = -(-x)^4 + 8(-x)^3 - 9(-x)^2 Simplify the right side of the function. s(-x) = -x^4 - 8x^3 - 9x^2Compare s(x) and s(-x): Compare s(x) and s(-x). We have s(x) = -x^4 + 8x^3 - 9x^2 and s(-x) = -x^4 - 8x^3 - 9x^2. Since s(-x) ≠ s(x) and s(-x) ≠ -s(x), s(x) is neither even nor odd.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Is the function $s(x) = -x^4 + 8x^3 - 9x^2$ even, odd, or neither? $\newline$ Choices: $\newline$ (A)even $\newline$ (B)odd $\newline$ (C)neither

View step-by-step help

Home

Math Problems

Algebra 2

Even and odd functions

Full solution

Q. Is the function

s(x) = -x^4 + 8x^3 - 9x^2

even, odd, or neither?

\newline

Choices:

\newline

(A)even

\newline

(B)odd

\newline

(C)neither

Substitute $-x$ in $s(x)$ : $s(x) = -x^4 + 8x^3 - 9x^2$ $\newline$ Find $s(-x)$ by substituting $-x$ for $x$ in $s(x)$ . $\newline$ $s(-x) = -(-x)^4 + 8(-x)^3 - 9(-x)^2$
Simplify $s(-x)$ : $s(-x) = -(-x)^4 + 8(-x)^3 - 9(-x)^2$ $\newline$ Simplify the right side of the function. $\newline$ $s(-x) = -x^4 - 8x^3 - 9x^2$
Compare $s(x)$ and $s(-x)$ : Compare $s(x)$ and $s(-x)$ . We have $s(x) = -x^4 + 8x^3 - 9x^2$ and $s(-x) = -x^4 - 8x^3 - 9x^2$ . Since $s(-x) \neq s(x)$ and $s(-x) \neq -s(x)$ , $s(x)$ is neither even nor odd.