Is the function n(x) = -x^4 + 3x^2 - 4 even, odd, or neither? Choices: (A)even (B)odd (C)neither

Substitute -x for x: n(x) = -x^4 + 3x^2 - 4 Find n(-x) by substituting -x for x. n(-x) = -(-x)^4 + 3(-x)^2 - 4Simplify the equation: n(-x) = -(-x)^4 + 3(-x)^2 - 4 Simplify the equation. n(-x) = -x^4 + 3x^2 - 4Compare n(x) and n(-x): Compare n(x) and n(-x). We got n(x) = -x^4 + 3x^2 - 4 and n(-x) = -x^4 + 3x^2 - 4. Since n(-x) = n(x), n(x) is an even function.

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Is the function $n(x) = -x^4 + 3x^2 - 4$ even, odd, or neither? $\newline$ Choices: $\newline$ (A)even $\newline$ (B)odd $\newline$ (C)neither

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Algebra 2

Even and odd functions

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Q. Is the function

n(x) = -x^4 + 3x^2 - 4

even, odd, or neither?

\newline

Choices:

\newline

(A)even

\newline

(B)odd

\newline

(C)neither

Substitute $-x$ for $x$ : $n(x) = -x^4 + 3x^2 - 4$ $\newline$ Find $n(-x)$ by substituting $-x$ for $x$ . $\newline$ $n(-x) = -(-x)^4 + 3(-x)^2 - 4$
Simplify the equation: $n(-x) = -(-x)^4 + 3(-x)^2 - 4$ $\newline$ Simplify the equation. $\newline$ $n(-x) = -x^4 + 3x^2 - 4$
Compare $n(x)$ and $n(-x)$ : Compare $n(x)$ and $n(-x)$ . We got $n(x) = -x^4 + 3x^2 - 4$ and $n(-x) = -(-x)^4 + 3(-x)^2 - 4$ . Since $n(-x) = n(x)$ , $n(x)$ is an even function.