Is the function h(x) = -3x^8 + x^4 - 2x^2 even, odd, or neither? Choices: (A)even (B)odd (C)neither

Calculate h(-x): Calculate h(-x) by substituting -x for x in the function h(x). h(-x) = -3(-x)^8 + (-x)^4 - 2(-x)^2Simplify h(-x): Simplify the function h(-x). h(-x) = -3x^8 + x^4 - 2x^2Compare h(x) and h(-x): Compare h(x) and h(-x). Since h(-x) = h(x), the function h(x) is even.

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Is the function $h(x) = -3x^8 + x^4 - 2x^2$ even, odd, or neither? $\newline$ Choices: $\newline$ (A)even $\newline$ (B)odd $\newline$ (C)neither

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Algebra 2

Even and odd functions

Full solution

Q. Is the function

h(x) = -3x^8 + x^4 - 2x^2

even, odd, or neither?

\newline

Choices:

\newline

(A)even

\newline

(B)odd

\newline

(C)neither

Calculate $h(-x)$ : Calculate $h(-x)$ by substituting $-x$ for $x$ in the function $h(x)$ . $\newline$ $h(-x) = -3(-x)^8 + (-x)^4 - 2(-x)^2$
Simplify $h(-x)$ : Simplify the function $h(-x)$ . $h(-x) = -3x^8 + x^4 - 2x^2$
Compare $h(x)$ and $h(-x)$ : Compare $h(x)$ and $h(-x)$ . $\newline$ Since $h(-x) = h(x)$ , the function $h(x)$ is even.