Q. Is the following function even, odd, or neither?f(x)=x2+23Choose 1 answer:(A) Even(B) Odd(C) Neither
Define function and f(−x): Define the function f(x) and determine f(−x). The given function is f(x)=x2+23. To determine if the function is even, odd, or neither, we need to evaluate f(−x) and compare it to f(x). Substitute −x for x in f(x)=x2+23. f(−x)=(−x)2+23
Simplify f(−x): Simplify f(−x). Simplify the right side of the function by noting that (−x)2 is equal to x2 because the square of a negative number is positive. f(−x)=x2+23
Compare f(x) and f(−x): Compare f(x) and f(−x). We have: f(x)=x2+23f(−x)=x2+23 Since f(−x)=f(x), the function f(x) is an even function.