Is the following function even, odd, or neither? f(x)=2^(x+3) Choose 1 answer: (A) Even (B) Odd (C) Neither

Determine Function Type: To determine if the function f(x) is even, odd, or neither, we need to compare f(x) with f(-x). If f(-x) = f(x), then the function is even. If f(-x) = -f(x), then the function is odd. If neither condition is met, the function is neither even nor odd.Substitute -x: Let's find f(-x) by substituting -x for x in the function f(x)=2^(x+3). f(-x) = 2^(-x+3)Compare f(-x) with f(x): Now, we need to compare f(-x) with f(x). We have f(x) = 2^(x+3) and f(-x) = 2^(-x+3). These two expressions are not the same, and f(-x) is not the negative of f(x), so the function is neither even nor odd.

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Is the following function even, odd, or neither? $\newline$ $f(x)=2^{(x+3)}$ $\newline$ Choose $1$ answer: $\newline$ (A) Even $\newline$ (B) Odd $\newline$ (C) Neither

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Algebra 2

Even and odd functions

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Q. Is the following function even, odd, or neither?

\newline

f(x)=2^{(x+3)}

\newline

Choose

1

answer:

\newline

(A) Even

\newline

(B) Odd

\newline

Determine Function Type: To determine if the function $f(x)$ is even, odd, or neither, we need to compare $f(x)$ with $f(-x)$ . If $f(-x) = f(x)$ , then the function is even. If $f(-x) = -f(x)$ , then the function is odd. If neither condition is met, the function is neither even nor odd.
Substitute $-x$ : Let's find $f(-x)$ by substituting $-x$ for $x$ in the function $f(x)=2^{(x+3)}$ . $\newline$ $f(-x) = 2^{(-x+3)}$
Compare $f(-x)$ with $f(x)$ : Now, we need to compare $f(-x)$ with $f(x)$ . We have $f(x) = 2^{(x+3)}$ and $f(-x) = 2^{(-x+3)}$ . These two expressions are not the same, and $f(-x)$ is not the negative of $f(x)$ , so the function is neither even nor odd.