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Is $(3,\ 10)$ a solution to the inequality $y \leq 3x + 1$ ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(3,\ 10)

a solution to the inequality

y \leq 3x + 1

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(3, 10)$ into the inequality $y \leq 3x + 1$ . The substituted inequality is $10 \leq 3(3) + 1$ .
Calculate right side: Calculate the right side of the inequality $3(3) + 1$ . This simplifies to $9 + 1$ , which equals $10$ .
Check if inequality is true: The inequality now reads $10 \leq 10$ . Determine if this is a true statement. Since $10$ is equal to $10$ , the inequality holds true.
Conclude solution validity: Since the inequality is true when the point $(3, 10)$ is substituted, we can conclude that $(3, 10)$ is indeed a solution to the inequality $y \leq 3x + 1$ .

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