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Is $(3,\,1)$ a solution to this system of inequalities? $\newline$ x + 12y < 15 $\newline$ $3x + 3y \leq 20$ $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Is (x, y) a solution to the system of linear inequalities?

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Q. Is

(3,\,1)

a solution to this system of inequalities?

\newline

x + 12y < 15

\newline

3x + 3y \leq 20

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Check Point: Does the point $(3, 1)$ satisfy the inequality x + 12y < 15? $\newline$ Substitute $3$ for $x$ and $1$ for $y$ in x + 12y < 15. $\newline$ 3 + 12(1) < 15 $\newline$ 3 + 12 < 15 $\newline$ 15 < 15 $\newline$ Since 15 < 15 is false (it should be x + 12y < 15 $1$ for equality), $(3, 1)$ does not satisfy x + 12y < 15.

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