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Is (2,6)(2,\,6) a solution to the inequality 5x+18y15x + 18y \leq 1 ?\newlineChoices:\newline(A)yes\newline(B)no

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Q. Is (2,6)(2,\,6) a solution to the inequality 5x+18y15x + 18y \leq 1 ?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute values into inequality: Substitute the values (2,6)(2, 6) into the inequality 5x+18y15x + 18y \leq 1. The substituted inequality is 5(2)+18(6)15(2) + 18(6) \leq 1.
  2. Calculate left side: Calculate the left side of the inequality 5(2)+18(6)5(2) + 18(6). Simplify 5(2)5(2) to get 1010 and 18(6)18(6) to get 108108.
  3. Add results: Add the results from Step 22 to get 10+10810 + 108, which equals 118118.
  4. Compare with right side: Compare the result from Step 33 with the right side of the inequality. We have 1181118 \leq 1. Determine if this statement is true or false.
  5. Evaluate statement: Since 118118 is not less than or equal to 11, the statement 1181118 \leq 1 is false. Therefore, the point (2,6)(2, 6) does not make the inequality 5x+18y15x + 18y \leq 1 true.

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