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Is $(2,\ 10)$ a solution to the inequality y > 3x + 1 ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(2,\ 10)

a solution to the inequality

y > 3x + 1

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute Values: Substitute the values $2, 10$ into the inequality y > 3x + 1. The substituted inequality is 10 > 3(2) + 1.
Calculate Right Side: Calculate the right side of the inequality $3(2) + 1$ . Simplify $3(2)$ to get $6$ , and then add $1$ to get $7$ .
Check Inequality: The inequality 10 > 3(2) + 1 becomes 10 > 7. Now, determine if the point $(2, 10)$ makes the inequality y > 3x + 1 true. 10 > 7 is a true statement. Therefore, the point $(2, 10)$ does satisfy the inequality y > 3x + 1.

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