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Is $(2,\,1)$ a solution to the inequality $4x + 6y \geq 17$ ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(2,\,1)

a solution to the inequality

4x + 6y \geq 17

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(2, 1)$ into the inequality $4x + 6y \geq 17$ . The substituted inequality is $4(2) + 6(1) \geq 17$ .
Calculate left side: Calculate the left side of the inequality $4(2) + 6(1)$ to find the sum. This simplifies to $8 + 6$ .
Add numbers: Add the numbers $8 + 6$ to get $14$ .
Determine truth of inequality: The inequality $4(2) + 6(1) \geq 17$ becomes $14 \geq 17$ . Now, determine if the point $(2, 1)$ makes the inequality $4x + 6y \geq 17$ true. Since $14$ is not greater than or equal to $17$ , the statement $14 \geq 17$ is false.

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