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Is $(1,\,5)$ a solution to the inequality $5x + 3y \leq 20$ ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(1,\,5)

a solution to the inequality

5x + 3y \leq 20

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(1, 5)$ into the inequality $5x + 3y \leq 20$ . The substituted inequality is $5(1) + 3(5) \leq 20$ .
Simplify left side: Simplify the left side of the inequality $5(1) + 3(5)$ to find the sum. This simplifies to $5 + 15$ , which equals $20$ .
Check if inequality holds true: The inequality $5(1) + 3(5) \leq 20$ becomes $20 \leq 20$ . Now, determine if the point $(1, 5)$ makes the inequality $5x + 3y \leq 20$ true. Since $20$ is equal to $20$ , the inequality holds true.

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