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Is $(1,\,3)$ a solution to the inequality $4x + 4y \leq 16$ ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(1,\,3)

a solution to the inequality

4x + 4y \leq 16

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(1, 3)$ into the inequality $4x + 4y \leq 16$ . The substituted inequality is $4(1) + 4(3) \leq 16$ .
Simplify left side: Simplify the left side of the inequality $4(1) + 4(3)$ to find the sum. This simplifies to $4 + 12$ , which equals $16$ .
Check if inequality holds true: The inequality $4(1) + 4(3) \leq 16$ becomes $16 \leq 16$ . Now, determine if the point $(1, 3)$ makes the inequality $4x + 4y \leq 16$ true. Since $16$ is equal to $16$ , the inequality holds true.

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