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In the year 2008 , a person bought a new car for 
$24500. For each consecutive year after that, the value of the car depreciated by 
11%. How much would the car be worth in the year 2012, to the nearest hundred dollars?
Answer:

In the year 20082008 , a person bought a new car for $24500 \$ 24500 . For each consecutive year after that, the value of the car depreciated by 11% 11 \% . How much would the car be worth in the year 20122012, to the nearest hundred dollars?\newlineAnswer:

Full solution

Q. In the year 20082008 , a person bought a new car for $24500 \$ 24500 . For each consecutive year after that, the value of the car depreciated by 11% 11 \% . How much would the car be worth in the year 20122012, to the nearest hundred dollars?\newlineAnswer:
  1. Determine initial value and rate: Determine the initial value of the car and the annual depreciation rate.\newlineThe initial value of the car is $24500\$24500, and it depreciates by 11%11\% each year.
  2. Calculate years depreciated: Calculate the number of years the car has depreciated by 20122012. From 20082008 to 20122012 is 44 years.
  3. Use exponential decay formula: Use the formula for exponential decay to find the value of the car after 44 years.\newlineThe formula is V=P(1r)tV = P(1 - r)^t, where VV is the final value, PP is the initial value, rr is the depreciation rate, and tt is the time in years.
  4. Substitute values into formula: Substitute the known values into the formula. V=24500(10.11)4V = 24500(1 - 0.11)^4
  5. Calculate depreciation factor: Calculate the depreciation factor.\newline10.11=0.891 - 0.11 = 0.89
  6. Raise factor to power: Raise the depreciation factor to the power of 44.0.8940.89^4
  7. Calculate value after 44 years: Calculate the value of the car after 44 years.\newlineV=24500×0.894V = 24500 \times 0.89^4\newlineV24500×0.6272V \approx 24500 \times 0.6272
  8. Perform multiplication for final value: Perform the multiplication to find the final value.\newlineV24500×0.627215366.4V \approx 24500 \times 0.6272 \approx 15366.4
  9. Round final value: Round the final value to the nearest hundred dollars.\newlineThe car would be worth approximately $15400\$15400 in the year 20122012.

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