In the year 2008 , a person bought a new car for $24500. For each consecutive year after that, the value of the car depreciated by 11%. How much would the car be worth in the year 2012, to the nearest hundred dollars?Answer:
Q. In the year 2008 , a person bought a new car for $24500. For each consecutive year after that, the value of the car depreciated by 11%. How much would the car be worth in the year 2012, to the nearest hundred dollars?Answer:
Determine initial value and rate: Determine the initial value of the car and the annual depreciation rate.The initial value of the car is $24500, and it depreciates by 11% each year.
Calculate years depreciated: Calculate the number of years the car has depreciated by 2012. From 2008 to 2012 is 4 years.
Use exponential decay formula: Use the formula for exponential decay to find the value of the car after 4 years.The formula is V=P(1−r)t, where V is the final value, P is the initial value, r is the depreciation rate, and t is the time in years.
Substitute values into formula: Substitute the known values into the formula. V=24500(1−0.11)4
Calculate depreciation factor: Calculate the depreciation factor.1−0.11=0.89
Raise factor to power: Raise the depreciation factor to the power of 4.0.894
Calculate value after 4 years: Calculate the value of the car after 4 years.V=24500×0.894V≈24500×0.6272
Perform multiplication for final value: Perform the multiplication to find the final value.V≈24500×0.6272≈15366.4
Round final value: Round the final value to the nearest hundred dollars.The car would be worth approximately $15400 in the year 2012.
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