Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

In the year 2004, a person bought a new car for 
$28000. For each consecutive year after that, the value of the car depreciated by 
13%. How much would the car be worth in the year 2007 , to the nearest hundred dollars?
Answer:

In the year 20042004, a person bought a new car for $28000 \$ 28000 . For each consecutive year after that, the value of the car depreciated by 13% 13 \% . How much would the car be worth in the year 20072007 , to the nearest hundred dollars?\newlineAnswer:

Full solution

Q. In the year 20042004, a person bought a new car for $28000 \$ 28000 . For each consecutive year after that, the value of the car depreciated by 13% 13 \% . How much would the car be worth in the year 20072007 , to the nearest hundred dollars?\newlineAnswer:
  1. Determine Depreciation Factor: Determine the depreciation factor.\newlineThe car depreciates by 13%13\% each year, which means it retains 87%87\% of its value each year (100%13%=87%100\% - 13\% = 87\%).\newlineThe depreciation factor is 0.870.87 (87%87\% expressed as a decimal).
  2. Calculate Value After One Year: Calculate the value of the car after one year.\newlineThe initial value of the car is $28000\$28000.\newlineAfter one year, the value is $28000×0.87\$28000 \times 0.87.
  3. Perform Calculation for One Year: Perform the calculation for one year.$28000×0.87=$24360.\$28000 \times 0.87 = \$24360.
  4. Repeat Depreciation Process: Repeat the depreciation process for each consecutive year. We need to apply the depreciation factor for three years (20042004 to 20072007).
  5. Calculate Value After Second Year: Calculate the value of the car after the second year.\newlineTake the value from the first year and multiply by the depreciation factor again.\newline$24360×0.87=$21193.20\$24360 \times 0.87 = \$21193.20.
  6. Calculate Value After Third Year: Calculate the value of the car after the third year.\newlineTake the value from the second year and multiply by the depreciation factor once more.\newline$21193.20×0.87=$18438.08\$21193.20 \times 0.87 = \$18438.08.
  7. Round Final Value: Round the final value to the nearest hundred dollars.\newlineThe value of the car in 20072007 is approximately $18400\$18400 when rounded to the nearest hundred.

More problems from Exponential growth and decay: word problems