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In the year 2000, a person bought a new car for 
$16500. For each consecutive year after that, the value of the car depreciated by 
6%. How much would the car be worth in the year 2003 , to the nearest hundred dollars?
Answer:

In the year 20002000, a person bought a new car for $16500 \$ 16500 . For each consecutive year after that, the value of the car depreciated by 6% 6 \% . How much would the car be worth in the year 20032003 , to the nearest hundred dollars?\newlineAnswer:

Full solution

Q. In the year 20002000, a person bought a new car for $16500 \$ 16500 . For each consecutive year after that, the value of the car depreciated by 6% 6 \% . How much would the car be worth in the year 20032003 , to the nearest hundred dollars?\newlineAnswer:
  1. Determine Initial Value and Rate: Determine the initial value of the car and the annual depreciation rate.\newlineThe initial value of the car is $16,500\$16,500, and it depreciates by 6%6\% each year.
  2. Calculate Depreciation Multiplier: Calculate the depreciation multiplier.\newlineThe car loses 6%6\% of its value each year, so it retains 94%94\% of its value each year (100%6%=94%100\% - 6\% = 94\%).\newlineTo find the multiplier, convert the percentage to a decimal: 94%=0.9494\% = 0.94.
  3. Determine Years Depreciated: Determine the number of years the car has depreciated.\newlineFrom the year 20002000 to the year 20032003 is 33 years.
  4. Apply Depreciation Formula: Apply the depreciation formula to calculate the car's value in 20032003.\newlineThe formula for depreciation is: Final Value=Initial Value×(Depreciation Multiplier)(Number of Years)\text{Final Value} = \text{Initial Value} \times (\text{Depreciation Multiplier})^{(\text{Number of Years})}.\newlineSubstitute the known values into the formula: Final Value=$(16,500)×(0.94)3\text{Final Value} = \$(16,500) \times (0.94)^3.
  5. Perform Calculation: Perform the calculation.\newlineFinal Value = $16,500×(0.94)3\$16,500 \times (0.94)^3\newlineFinal Value = $16,500×0.830584\$16,500 \times 0.830584 (0.940.94 cubed is approximately 0.8305840.830584)\newlineFinal Value = $13,711.64\$13,711.64
  6. Round Final Value: Round the final value to the nearest hundred dollars.\newlineThe value of the car in 20032003, rounded to the nearest hundred dollars, is approximately $13,700\$13,700.

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