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In one kind of chemical reaction, unconverted reactants change into converted reactants.
The fraction 
a of reactants that have been converted increases at a rate proportional to the product of the fraction of converted reactants and the fraction of unconverted reactants.
Which equation describes this relationship?
Choose 1 answer:
(A) 
(da)/(dt)=(ka)/(1-a)
(B) 
(da)/(dt)=ka^(2)
(C) 
(da)/(dt)=ka(1-a)
(D) 
(da)/(dt)=(k)/(a(1-a))

In one kind of chemical reaction, unconverted reactants change into converted reactants.\newlineThe fraction a a of reactants that have been converted increases at a rate proportional to the product of the fraction of converted reactants and the fraction of unconverted reactants.\newlineWhich equation describes this relationship?\newlineChoose 11 answer:\newline(A) dadt=ka1a \frac{d a}{d t}=\frac{k a}{1-a} \newline(B) dadt=ka2 \frac{d a}{d t}=k a^{2} \newline(C) dadt=ka(1a) \frac{d a}{d t}=k a(1-a) \newline(D) dadt=ka(1a) \frac{d a}{d t}=\frac{k}{a(1-a)}

Full solution

Q. In one kind of chemical reaction, unconverted reactants change into converted reactants.\newlineThe fraction a a of reactants that have been converted increases at a rate proportional to the product of the fraction of converted reactants and the fraction of unconverted reactants.\newlineWhich equation describes this relationship?\newlineChoose 11 answer:\newline(A) dadt=ka1a \frac{d a}{d t}=\frac{k a}{1-a} \newline(B) dadt=ka2 \frac{d a}{d t}=k a^{2} \newline(C) dadt=ka(1a) \frac{d a}{d t}=k a(1-a) \newline(D) dadt=ka(1a) \frac{d a}{d t}=\frac{k}{a(1-a)}
  1. Denote Fraction of Reactants: Let's denote the fraction of reactants that have been converted by a a . According to the problem, the rate of change of a a with respect to time t t , which is dadt \frac{da}{dt} , is proportional to the product of the fraction of converted reactants a a and the fraction of unconverted reactants 1a 1 - a . The constant of proportionality is k k . Therefore, the equation that describes this relationship is dadt=ka(1a) \frac{da}{dt} = k \cdot a \cdot (1 - a) .
  2. Rate of Change Equation: We can now compare the given options with our derived equation. Option (A) dadt=ka1a \frac{da}{dt} = \frac{ka}{1 - a} does not match because it suggests the rate is inversely proportional to the fraction of unconverted reactants, which is not what the problem states.
  3. Comparison with Options: Option (B) dadt=ka2 \frac{da}{dt} = ka^2 suggests the rate is proportional to the square of the fraction of converted reactants, which again is not what the problem states.
  4. Option (A) Analysis: Option (C) dadt=ka(1a) \frac{da}{dt} = ka(1 - a) matches our derived equation exactly, indicating that the rate of conversion is proportional to both the fraction of converted reactants and the fraction of unconverted reactants.
  5. Option (B) Analysis: Option (D) dadt=ka(1a) \frac{da}{dt} = \frac{k}{a(1 - a)} suggests the rate is inversely proportional to the product of the fraction of converted and unconverted reactants, which is incorrect according to the problem statement.

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