In /_\HIJ,m/_H=(6x+10)^(@),m/_I=(3x-6)^(@), and m/_J=(6x+11)^(@). Find m/_J. Answer:

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In  /_\HIJ,m/_H=(6x+10)^(@),m/_I=(3x-6)^(@), and  m/_J=(6x+11)^(@). Find  m/_J. Answer:

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Recognize Triangle Angle Sum: First, recognize that the sum of the angles in any triangle is 180 degrees.Write Equation for Triangle HIJ: Write an equation that represents the sum of the angles in triangle HIJ. m/_H + m/_I + m/_J = 180^(@)Substitute Given Expressions: Substitute the given expressions for m/_H, m/_I, and m/_J into the equation. (6x + 10)^(@) + (3x - 6)^(@) + (6x + 11)^(@) = 180^(@)Combine Like Terms: Combine like terms to simplify the equation. 6x + 10 + 3x - 6 + 6x + 11 = 180Isolate Variable Term: Further simplify the equation by combining like terms. 15x + 15 = 180Solve for x: Subtract 15 from both sides to isolate the term with the variable x. 15x + 15 - 15 = 180 - 15 15x = 165Substitute x into m/_J Expression: Divide both sides by 15 to solve for x. 15x / 15 = 165 / 15 x = 11Calculate m/_J Value: Now that we have the value of x, substitute it back into the expression for m/_J to find the measure of angle J. m/_J = (6x + 11)^(@) m/_J = (6(11) + 11)^(@)Calculate the value of m/_J. m/_J = (66 + 11)^(@) m/_J = 77^(@)

In $\triangle \mathrm{HIJ}, \mathrm{m} \angle H=(6 x+10)^{\circ}, \mathrm{m} \angle I=(3 x-6)^{\circ}$ , and $\mathrm{m} \angle J=(6 x+11)^{\circ}$ . $\newline$ Find $\mathrm{m} \angle J$ . $\newline$ Answer:

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