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In an experiment, the probability that event AA occurs is 59\frac{5}{9}, the probability that event BB occurs is 25\frac{2}{5}, and the probability that events AA and BB both occur is 19\frac{1}{9}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 59\frac{5}{9}, the probability that event BB occurs is 25\frac{2}{5}, and the probability that events AA and BB both occur is 19\frac{1}{9}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, let's find the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(59)×(25)P(A) \times P(B) = \left(\frac{5}{9}\right) \times \left(\frac{2}{5}\right)
  3. Multiply Probabilities: Now, let's do the multiplication.\newline(59)×(25)=1045(\frac{5}{9}) \times (\frac{2}{5}) = \frac{10}{45}
  4. Simplify Result: We simplify 1045\frac{10}{45} to its lowest terms.\newline1045=29\frac{10}{45} = \frac{2}{9}
  5. Compare Probabilities: Now we compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineP(A and B)=19P(A \text{ and } B) = \frac{1}{9}\newlineP(A)×P(B)=29P(A) \times P(B) = \frac{2}{9}
  6. Determine Independence: Since P(A and B)P(A)×P(B)P(A \text{ and } B) \neq P(A) \times P(B), events AA and BB are not independent.

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