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In an experiment, the probability that event AA occurs is 12\frac{1}{2}, the probability that event BB occurs is 47\frac{4}{7}, and the probability that events AA and BB both occur is 17\frac{1}{7}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 12\frac{1}{2}, the probability that event BB occurs is 47\frac{4}{7}, and the probability that events AA and BB both occur is 17\frac{1}{7}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no
  1. Calculate product of probabilities: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B): First, calculate the product of P(A)P(A) and P(B)P(B).P(A)×P(B)=(12)×(47)=414=27P(A) \times P(B) = \left(\frac{1}{2}\right) \times \left(\frac{4}{7}\right) = \frac{4}{14} = \frac{2}{7}.
  3. Conclusion: Now, compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineP(A and B)=17P(A \text{ and } B) = \frac{1}{7}, but we calculated P(A)×P(B)=27P(A) \times P(B) = \frac{2}{7}.
  4. Conclusion: Now, compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B). P(A and B)=17P(A \text{ and } B) = \frac{1}{7}, but we calculated P(A)×P(B)=27P(A) \times P(B) = \frac{2}{7}. Since P(A and B)P(A \text{ and } B) is not equal to P(A)×P(B)P(A) \times P(B), events AA and BB are not independent.

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