Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

In an experiment, the probability that event AA occurs is 79\frac{7}{9}, the probability that event BB occurs is 37\frac{3}{7}, and the probability that events AA and BB both occur is 29\frac{2}{9}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 79\frac{7}{9}, the probability that event BB occurs is 37\frac{3}{7}, and the probability that events AA and BB both occur is 29\frac{2}{9}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check for Independence: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(79)×(37)P(A) \times P(B) = \left(\frac{7}{9}\right) \times \left(\frac{3}{7}\right)
  3. Simplify Product: Now, simplify the product. P(A)×P(B)=7×39×7=2163P(A) \times P(B) = \frac{7 \times 3}{9 \times 7} = \frac{21}{63}
  4. Reduce Fraction: Reduce the fraction 2163\frac{21}{63} to its simplest form.\newline2163=13\frac{21}{63} = \frac{1}{3}
  5. Compare Probabilities: Now, compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineP(A and B)=29P(A \text{ and } B) = \frac{2}{9}\newlineP(A)×P(B)=13P(A) \times P(B) = \frac{1}{3}
  6. Determine Independence: Since 29\frac{2}{9} is not equal to 13\frac{1}{3}, events AA and BB are not independent.

More problems from Identify independent events