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In an experiment, the probability that event $A$ occurs is $\frac{1}{8}$ and the probability that event $B$ occurs is $\frac{7}{8}$ . If $A$ and $B$ are independent events, what is the probability that $A$ and $B$ both occur? $\newline$ Simplify any fractions.

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Independence and conditional probability

Full solution

Q. In an experiment, the probability that event

A

occurs is

\frac{1}{8}

and the probability that event

B

occurs is

\frac{7}{8}

. If

A

and

B

are independent events, what is the probability that

A

and

B

both occur?

\newline

Simplify any fractions.

Question Prompt: question_prompt: What's the probability that both event $A$ and event $B$ happen if they're independent?
Calculation of P(A and B): $P(A \text{ and } B) = P(A) \times P(B)$ cuz they're independent, so let's multiply the probabilities of $A$ and $B$ .
Calculate $P(A)$ and $P(B)$ : $P(A) = \frac{1}{8}$ and $P(B) = \frac{7}{8}$ , so $P(A \text{ and } B) = \frac{1}{8} \times \frac{7}{8}$ .
Multiply Probabilities: Now, do the math: $\frac{1}{8} \times \frac{7}{8} = \frac{7}{64}$ .
Final Probability: No need to simplify, $7/64$ is already as simple as it gets.

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\newline

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\newline

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\newline

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