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In an experiment, the probability that event AA occurs is 27\frac{2}{7}, the probability that event BB occurs is 56\frac{5}{6}, and the probability that events AA and BB both occur is 521\frac{5}{21}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 27\frac{2}{7}, the probability that event BB occurs is 56\frac{5}{6}, and the probability that events AA and BB both occur is 521\frac{5}{21}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B).P(A)×P(B)=27×56P(A) \times P(B) = \frac{2}{7} \times \frac{5}{6}
  3. Multiply Probabilities: Now, do the multiplication.\newline(27)×(56)=1042(\frac{2}{7}) \times (\frac{5}{6}) = \frac{10}{42}
  4. Simplify Fraction: Simplify the fraction 1042\frac{10}{42} to its lowest terms.\newline1042=521\frac{10}{42} = \frac{5}{21}
  5. Compare P(A and B)P(A \text{ and } B) with Product: Now, compare P(A and B)P(A \text{ and } B) with the product of P(A)×P(B)P(A) \times P(B).P(A and B)=521P(A \text{ and } B) = \frac{5}{21} and P(A)×P(B)=521P(A) \times P(B) = \frac{5}{21}
  6. Confirm Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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