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In an experiment, the probability that event AA occurs is 49\frac{4}{9}, the probability that event BB occurs is 59\frac{5}{9}, and the probability that events AA and BB both occur is 2081\frac{20}{81}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 49\frac{4}{9}, the probability that event BB occurs is 59\frac{5}{9}, and the probability that events AA and BB both occur is 2081\frac{20}{81}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B).P(A)×P(B)=(49)×(59)P(A) \times P(B) = \left(\frac{4}{9}\right) \times \left(\frac{5}{9}\right)
  3. Perform Multiplication: Now, do the multiplication.\newline(49)×(59)=2081(\frac{4}{9}) \times (\frac{5}{9}) = \frac{20}{81}
  4. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineSince P(A and B)=2081P(A \text{ and } B) = \frac{20}{81} and P(A)×P(B)=2081P(A) \times P(B) = \frac{20}{81}, they are equal.
  5. Determine Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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