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In an experiment, the probability that event AA occurs is 37\frac{3}{7}, the probability that event BB occurs is 23\frac{2}{3}, and the probability that events AA and BB both occur is 17\frac{1}{7}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 37\frac{3}{7}, the probability that event BB occurs is 23\frac{2}{3}, and the probability that events AA and BB both occur is 17\frac{1}{7}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(37)×(23)P(A) \times P(B) = \left(\frac{3}{7}\right) \times \left(\frac{2}{3}\right)
  3. Multiply Probabilities: Now, do the multiplication.\newline(37)×(23)=621(\frac{3}{7}) \times (\frac{2}{3}) = \frac{6}{21}
  4. Simplify Fraction: Simplify the fraction 621\frac{6}{21} to its lowest terms.\newline621=27\frac{6}{21} = \frac{2}{7}
  5. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineP(A and B)=17P(A \text{ and } B) = \frac{1}{7}\newlineP(A)×P(B)=27P(A) \times P(B) = \frac{2}{7}\newlineSince 17\frac{1}{7} is not equal to 27\frac{2}{7}, events AA and BB are not independent.

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