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In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 58\frac{5}{8}, and the probability that events AA and BB both occur is 18\frac{1}{8}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 58\frac{5}{8}, and the probability that events AA and BB both occur is 18\frac{1}{8}. \newlineAre AA and BB independent events? \newlineChoices: \newline(A) yes \newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(25)×(58)P(A) \times P(B) = \left(\frac{2}{5}\right) \times \left(\frac{5}{8}\right)
  3. Perform Multiplication: Perform the multiplication. (25)×(58)=1040(\frac{2}{5}) \times (\frac{5}{8}) = \frac{10}{40}
  4. Simplify Fraction: Simplify the fraction. 1040=14\frac{10}{40} = \frac{1}{4}
  5. Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B): Now, compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).P(A and B)=18P(A \text{ and } B) = \frac{1}{8}P(A)×P(B)=14P(A) \times P(B) = \frac{1}{4}
  6. Conclusion: Since P(A and B)P(A \text{ and } B) is not equal to P(A)×P(B)P(A) \times P(B), events AA and BB are not independent.

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