Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

In an experiment, the probability that event AA occurs is 15\frac{1}{5}, the probability that event BB occurs is 16\frac{1}{6}, and the probability that events AA and BB both occur is 130\frac{1}{30}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 15\frac{1}{5}, the probability that event BB occurs is 16\frac{1}{6}, and the probability that events AA and BB both occur is 130\frac{1}{30}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=15×16P(A) \times P(B) = \frac{1}{5} \times \frac{1}{6}
  3. Perform Multiplication: Now, do the multiplication.\newline(15)×(16)=130(\frac{1}{5}) \times (\frac{1}{6}) = \frac{1}{30}
  4. Compare Probabilities: Compare the product of P(A)P(A) and P(B)P(B) with P(A and B)P(A \text{ and } B).\newlineSince P(A and B)=130P(A \text{ and } B) = \frac{1}{30} and P(A)×P(B)=130P(A) \times P(B) = \frac{1}{30}, they are equal.
  5. Confirm Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

More problems from Identify independent events