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In an experiment, the probability that event AA occurs is 78\frac{7}{8}, the probability that event BB occurs is 79\frac{7}{9}, and the probability that events AA and BB both occur is 4972\frac{49}{72}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no

Full solution

Q. In an experiment, the probability that event AA occurs is 78\frac{7}{8}, the probability that event BB occurs is 79\frac{7}{9}, and the probability that events AA and BB both occur is 4972\frac{49}{72}. Are AA and BB independent events?\newlineChoices:\newline(A) yes\newline(B) no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(78)×(79)P(A) \times P(B) = \left(\frac{7}{8}\right) \times \left(\frac{7}{9}\right)
  3. Perform Multiplication: Now, do the multiplication.\newline(78)×(79)=4972(\frac{7}{8}) \times (\frac{7}{9}) = \frac{49}{72}
  4. Compare Probabilities: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineSince P(A and B)=4972P(A \text{ and } B) = \frac{49}{72} and P(A)×P(B)=4972P(A) \times P(B) = \frac{49}{72}, they are equal.
  5. Determine Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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