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In an experiment, the probability that event $A$ occurs is $\frac{5}{8}$ , the probability that event $B$ occurs is $\frac{1}{4}$ , and the probability that events $A$ and $B$ both occur is $\frac{1}{9}$ . What is the probability that $A$ occurs given that $B$ occurs? $\newline$ Simplify any fractions.

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Find conditional probabilities

Full solution

Q. In an experiment, the probability that event

A

occurs is

\frac{5}{8}

, the probability that event

B

occurs is

\frac{1}{4}

, and the probability that events

A

and

B

both occur is

\frac{1}{9}

. What is the probability that

A

occurs given that

B

occurs?

\newline

Simplify any fractions.

Identify Conditional Probability Formula: To find the probability that $A$ occurs given that $B$ occurs, we use the formula for conditional probability: $P(A|B) = \frac{P(A \text{ and } B)}{P(B)}$ .
Calculate $P(A \text{ and } B)$ and $P(B)$ : We know $P(A \text{ and } B) = \frac{1}{9}$ and $P(B) = \frac{1}{4}$ . So, $P(A|B) = \frac{\frac{1}{9}}{\frac{1}{4}}$ .
Calculate $P(A|B)$ : To divide fractions, we multiply by the reciprocal of the divisor. So, $P(A|B) = \frac{1}{9} \times \frac{4}{1} = \frac{4}{9}$ .

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