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In an experiment, the probability that event AA occurs is 34\frac{3}{4}, the probability that event BB occurs is 57\frac{5}{7}, and the probability that events AA and BB both occur is 1528\frac{15}{28}. Are AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no

Full solution

Q. In an experiment, the probability that event AA occurs is 34\frac{3}{4}, the probability that event BB occurs is 57\frac{5}{7}, and the probability that events AA and BB both occur is 1528\frac{15}{28}. Are AA and BB independent events?\newlineChoices:\newline(A)yes\newline(B)no
  1. Check Independence Criteria: To check if events AA and BB are independent, we need to see if the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Product of Probabilities: First, calculate the product of P(A)P(A) and P(B)P(B). \newlineP(A)×P(B)=(34)×(57)P(A) \times P(B) = \left(\frac{3}{4}\right) \times \left(\frac{5}{7}\right)
  3. Multiply Probabilities: Now, do the multiplication.\newline(34)×(57)=1528(\frac{3}{4}) \times (\frac{5}{7}) = \frac{15}{28}
  4. Compare Results: Compare P(A and B)P(A \text{ and } B) with P(A)×P(B)P(A) \times P(B).\newlineSince P(A and B)=1528P(A \text{ and } B) = \frac{15}{28} and P(A)×P(B)=1528P(A) \times P(B) = \frac{15}{28}, they are equal.
  5. Confirm Independence: Since P(A and B)P(A \text{ and } B) is equal to P(A)×P(B)P(A) \times P(B), events AA and BB are independent.

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