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In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 56\frac{5}{6}, and the probability that events AA and BB both occur is 13\frac{1}{3}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.

Full solution

Q. In an experiment, the probability that event AA occurs is 25\frac{2}{5}, the probability that event BB occurs is 56\frac{5}{6}, and the probability that events AA and BB both occur is 13\frac{1}{3}. What is the probability that AA occurs given that BB occurs? Simplify any fractions.
  1. Use Formula: To find the probability of A given B, we use the formula P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}.
  2. Calculate Probabilities: We know P(A and B)=13P(A \text{ and } B) = \frac{1}{3} and P(B)=56P(B) = \frac{5}{6}.
  3. Divide Fractions: Now we calculate P(AB)=13/56P(A|B) = \frac{1}{3} / \frac{5}{6}.
  4. Simplify Result: To divide fractions, we multiply by the reciprocal of the second fraction: (13)×(65)(\frac{1}{3}) \times (\frac{6}{5}).
  5. Simplify Result: To divide fractions, we multiply by the reciprocal of the second fraction: (13)×(65)(\frac{1}{3}) \times (\frac{6}{5}).Multiplying the numerators: 1×6=61 \times 6 = 6.\newlineMultiplying the denominators: 3×5=153 \times 5 = 15.
  6. Simplify Result: To divide fractions, we multiply by the reciprocal of the second fraction: (13)×(65)(\frac{1}{3}) \times (\frac{6}{5}).Multiplying the numerators: 1×6=61 \times 6 = 6.\newlineMultiplying the denominators: 3×5=153 \times 5 = 15.So, P(AB)=615P(A|B) = \frac{6}{15}.
  7. Simplify Result: To divide fractions, we multiply by the reciprocal of the second fraction: (13)×(65)(\frac{1}{3}) \times (\frac{6}{5}).Multiplying the numerators: 1×6=61 \times 6 = 6. Multiplying the denominators: 3×5=153 \times 5 = 15.So, P(AB)=615P(A|B) = \frac{6}{15}.We can simplify 615\frac{6}{15} by dividing both numerator and denominator by their greatest common divisor, which is 33.
  8. Simplify Result: To divide fractions, we multiply by the reciprocal of the second fraction: (13)×(65)(\frac{1}{3}) \times (\frac{6}{5}). Multiplying the numerators: 1×6=61 \times 6 = 6. Multiplying the denominators: 3×5=153 \times 5 = 15. So, P(AB)=615P(A|B) = \frac{6}{15}. We can simplify 615\frac{6}{15} by dividing both numerator and denominator by their greatest common divisor, which is 33. After simplifying, we get P(AB)=25P(A|B) = \frac{2}{5}.

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