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In an experiment, the probability that event $A$ occurs is $\frac{6}{7}$ , the probability that event $B$ occurs is $\frac{1}{7}$ , and the probability that events $A$ and $B$ both occur is $\frac{6}{49}$ . $\newline$ Are $A$ and $B$ independent events? $\newline$ (A) yes $\newline$ (B) no

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Identify independent events

Full solution

Q. In an experiment, the probability that event

A

occurs is

\frac{6}{7}

, the probability that event

B

occurs is

\frac{1}{7}

, and the probability that events

A

and

B

both occur is

\frac{6}{49}

.

\newline

Are

A

and

B

independent events?

\newline

(A) yes

\newline

(B) no

Check Independence Criteria: To check if events $A$ and $B$ are independent, we need to see if the probability of $A$ and $B$ occurring together ( $P(A \text{ and } B)$ ) is equal to the product of their individual probabilities ( $P(A) \times P(B)$ ).
Calculate Product of Probabilities: First, let's find the product of $P(A)$ and $P(B)$ . $P(A) \times P(B) = \left(\frac{6}{7}\right) \times \left(\frac{1}{7}\right)$
Compare $P(A \text{ and } B)$ with $P(A) \times P(B)$ : Now, calculate the product. $\newline$ $P(A) \times P(B) = \frac{6}{49}$
Events $A$ and $B$ are Independent: Next, compare $P(A \text{ and } B)$ with $P(A) \times P(B)$ . $\newline$ $P(A \text{ and } B) = \frac{6}{49}$ and $P(A) \times P(B) = \frac{6}{49}$
Events A and B are Independent: Next, compare $P(A \text{ and } B)$ with $P(A) \times P(B)$ . $P(A \text{ and } B) = \frac{6}{49}$ and $P(A) \times P(B) = \frac{6}{49}$ . Since $P(A \text{ and } B)$ is equal to $P(A) \times P(B)$ , events A and B are independent.

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