In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 6 boys and 15 girls are competing, how many different ways could the six medals possibly be given out?Answer:
Q. In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 6 boys and 15 girls are competing, how many different ways could the six medals possibly be given out?Answer:
Calculate Boys Medals: Calculate the number of ways to give out medals to the boys.Since there are 6 boys and 3 medals (gold, silver, bronze), we use permutations because the order matters (gold is different from silver, which is different from bronze).Number of ways to give out medals to the boys = 6P3=(6−3)!6!
Calculate Boys Medals Result: Perform the calculation for the number of ways to give out medals to the boys.6!/3!=(6×5×4×3×2×1)/(3×2×1)=6×5×4=120
Calculate Girls Medals: Calculate the number of ways to give out medals to the girls.Since there are 15 girls and 3 medals, we again use permutations.Number of ways to give out medals to the girls = 15P3=(15−3)!15!
Calculate Girls Medals Result: Perform the calculation for the number of ways to give out medals to the girls. 15!/12!=(15×14×13×12×11×…×1)/(12×11×…×1)=15×14×13=2730
Calculate Total Ways: Calculate the total number of different ways the six medals can be given out.Since the medal distribution for boys and girls are independent events, we multiply the number of ways for boys by the number of ways for girls.Total number of ways = Number of ways for boys × Number of ways for girls
Calculate Total Ways Result: Perform the final calculation to find the total number of different ways the six medals can be given out.Total number of ways = 120 (for boys) ×2730 (for girls) = 327600