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In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 13 boys and 5 girls are competing, how many different ways could the six medals possibly be given out?
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In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 1313 boys and 55 girls are competing, how many different ways could the six medals possibly be given out?\newlineAnswer:

Full solution

Q. In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 1313 boys and 55 girls are competing, how many different ways could the six medals possibly be given out?\newlineAnswer:
  1. Calculate Boys' Medal Permutations: First, we need to calculate the number of ways the medals can be given out to the boys. Since there are 1313 boys and 33 medals (gold, silver, bronze), we use permutations because the order in which the medals are awarded matters.\newlineThe number of ways to award 33 medals to 1313 boys is given by the permutation formula:\newlineP(n,k)=n!(nk)!P(n, k) = \frac{n!}{(n - k)!}\newlinewhere nn is the total number of boys and kk is the number of medals.
  2. Calculate Girls' Medal Permutations: For the boys, we calculate the permutation:\newlineP(13,3)=13!(133)!P(13, 3) = \frac{13!}{(13 - 3)!}\newlineP(13,3)=13!10!P(13, 3) = \frac{13!}{10!}\newlineP(13,3)=13×12×11P(13, 3) = 13 \times 12 \times 11\newlineP(13,3)=1716P(13, 3) = 1716\newlineSo, there are 17161716 different ways to award the medals to the boys.
  3. Calculate Total Ways: Next, we calculate the number of ways the medals can be given out to the girls. Since there are 55 girls and 33 medals, we again use permutations.\newlineP(5,3)=5!(53)!P(5, 3) = \frac{5!}{(5 - 3)!}\newlineP(5,3)=5!2!P(5, 3) = \frac{5!}{2!}\newlineP(5,3)=5×4×3P(5, 3) = 5 \times 4 \times 3\newlineP(5,3)=60P(5, 3) = 60\newlineSo, there are 6060 different ways to award the medals to the girls.
  4. Perform Multiplication: Finally, to find the total number of different ways the six medals can be given out, we multiply the number of ways for the boys by the number of ways for the girls.\newlineTotal ways =Ways for boys×Ways for girls= \text{Ways for boys} \times \text{Ways for girls}\newlineTotal ways =1716×60= 1716 \times 60
  5. Perform Multiplication: Finally, to find the total number of different ways the six medals can be given out, we multiply the number of ways for the boys by the number of ways for the girls.\newlineTotal ways =Ways for boys×Ways for girls= \text{Ways for boys} \times \text{Ways for girls}\newlineTotal ways =1716×60= 1716 \times 60 We perform the multiplication to find the total number of ways:\newlineTotal ways =1716×60= 1716 \times 60\newlineTotal ways =102960= 102960\newlineSo, there are 102960102960 different ways the six medals can be given out.

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