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In a certain Algebra 2 class of 30 students, 16 of them play basketball and 10 of them play baseball. There are 8 students who play neither sport. What is the probability that a student chosen randomly from the class plays basketball or baseball?
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In a certain Algebra 22 class of 3030 students, 1616 of them play basketball and 1010 of them play baseball. There are 88 students who play neither sport. What is the probability that a student chosen randomly from the class plays basketball or baseball?\newlineAnswer:

Full solution

Q. In a certain Algebra 22 class of 3030 students, 1616 of them play basketball and 1010 of them play baseball. There are 88 students who play neither sport. What is the probability that a student chosen randomly from the class plays basketball or baseball?\newlineAnswer:
  1. Determine Total Students: First, let's determine the total number of students who play either basketball or baseball. Since some students might play both sports, we cannot simply add the number of basketball players to the number of baseball players. We need to use the principle of inclusion-exclusion.
  2. Principle of Inclusion-Exclusion: According to the principle of inclusion-exclusion, the number of students who play basketball or baseball is equal to the number of basketball players plus the number of baseball players minus the number of students who play both sports.
  3. Find Students Who Play Both: We can find the number of students who play both sports by subtracting the number of students who play neither sport from the total number of students, and then subtracting the number of students who play only one sport (basketball or baseball).
  4. Calculate Students Who Play One Sport: The number of students who play only one sport is the total number of students minus the number of students who play neither sport: 3030 students - 88 students == 2222 students.
  5. Calculate Students Who Play Both: Now, we subtract the number of students who play only one sport from the sum of basketball and baseball players to find the number of students who play both: 1616 basketball players ++ 1010 baseball players\) - 2222 students == 44 students who play both sports.
  6. Apply Inclusion-Exclusion Principle: Using the principle of inclusion-exclusion, the number of students who play basketball or baseball is: 1616 basketball players + 1010 baseball players - 44 students who play both = 2222 students.
  7. Calculate Probability: The probability that a student chosen randomly from the class plays basketball or baseball is the number of students who play basketball or baseball divided by the total number of students in the class.
  8. Final Probability Calculation: Calculating the probability: 2222 students who play basketball or baseball // 3030 total students == 11/1511/15.

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