An object moves in simple harmonic motion with amplitude 13cm and period 0.25seconds. At time t=0seconds, its displacement d from rest is 0cm, and initially it moves in a positive direction.Give the equation modeling the displacement d as a function of time t.d=□
Q. An object moves in simple harmonic motion with amplitude 13cm and period 0.25seconds. At time t=0seconds, its displacement d from rest is 0cm, and initially it moves in a positive direction.Give the equation modeling the displacement d as a function of time t.d=□
Equation for Simple Harmonic Motion: The general form of the equation for simple harmonic motion is d(t)=A⋅sin(ωt+φ), where A is the amplitude, ω is the angular frequency, and φ is the phase shift.
Given Amplitude: The amplitude A is given as 13 cm, so A=13.
Calculate Angular Frequency: The period T is given as 0.25 seconds. The angular frequency ω is related to the period by the formula ω=T2π.
Calculate Phase Shift: Calculate the angular frequency: ω=0.252π=8π.
Plug Values into Equation: Since the object starts at rest and moves in a positive direction at t=0, the phase shift φ is 0.
Simplify Equation: Plug the values of A, ω, and φ into the general equation: d(t)=13×sin(8πt+0).
Simplify Equation: Plug the values of A, ω, and φ into the general equation: d(t)=13×sin(8πt+0).Simplify the equation: d(t)=13×sin(8πt).
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