Q. If −y+x+y2+5y3+3x2=0 then find dxdy in terms of x and y.Answer: dxdy=
Given Equation: We are given the equation −y+x+y2+5y3+3x2=0 and we need to find the derivative of y with respect to x, which is dxdy. To do this, we will use implicit differentiation, which involves taking the derivative of both sides of the equation with respect to x, while treating y as a function of x.
Implicit Differentiation: First, we differentiate each term of the equation with respect to x. For the terms involving only x, we use the standard rules of differentiation. For the terms involving y, we use the chain rule, remembering to multiply by dxdy since y is a function of x. The derivative of −y with respect to x is −1dxdy. The derivative of x with respect to x is x1. The derivative of x2 with respect to x is x4. The derivative of x5 with respect to x is x7. The derivative of x8 with respect to x is y0.
Differentiating Terms: Now we write down the differentiated equation:−1dxdy+1+2ydxdy+15y2dxdy+6x=0
Writing Differentiated Equation: Next, we collect all the terms involving dxdy on one side and the terms not involving dxdy on the other side:\(-1\frac{dy}{dx} + 2y\frac{dy}{dx} + 15y^{2}\frac{dy}{dx} = −1 - 6x
Solving for (dxdy):</b>Wefactorout$(dxdy) from the left side of the equation:(\frac{dy}{dx})(\(-1 + 2y + 15y^{2}) = −1 - 6x
Solving for (dxdy):</b>Wefactorout$(dxdy) from the left side of the equation:(dxdy)(−1+2y+15y2)=−1−6xNow we solve for (dxdy) by dividing both sides of the equation by (−1+2y+15y2):(dxdy)=−1+2y+15y2−1−6x