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If x=23yx=\frac{2}{3}y and y=18y=18, what is the value of 2x32x-3?\newlineA) 2121\newlineB) 1515\newlineC) 1212\newlineD) 1010

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Q. If x=23yx=\frac{2}{3}y and y=18y=18, what is the value of 2x32x-3?\newlineA) 2121\newlineB) 1515\newlineC) 1212\newlineD) 1010
  1. Given Equation: Given: x=23yx = \frac{2}{3}y and y=18y = 18. We need to find the value of xx first.\newlinex=23yx = \frac{2}{3}y\newlineSubstitute yy with 1818.\newlinex=23×18x = \frac{2}{3}\times18\newlineCalculate the value of xx.\newlinex=2×6x = 2\times6\newlinex=12x = 12
  2. Find xx: Now we have the value of xx, we can find the value of 2x32x-3.\newline2x3=2×1232x - 3 = 2\times12 - 3\newlineCalculate the expression.\newline2x3=2432x - 3 = 24 - 3\newline2x3=212x - 3 = 21

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